t^2-10t+50=0

Solution for t^2-10t+50=0 equation:

Simplifying
t2 + -10t + 50 = 0

Reorder the terms:
50 + -10t + t2 = 0

Solving
50 + -10t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-50' to each side of the equation.
50 + -10t + -50 + t2 = 0 + -50

Reorder the terms:
50 + -50 + -10t + t2 = 0 + -50

Combine like terms: 50 + -50 = 0
0 + -10t + t2 = 0 + -50
-10t + t2 = 0 + -50

Combine like terms: 0 + -50 = -50
-10t + t2 = -50

The t term is -10t.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10t + 25 + t2 = -50 + 25

Reorder the terms:
25 + -10t + t2 = -50 + 25

Combine like terms: -50 + 25 = -25
25 + -10t + t2 = -25

Factor a perfect square on the left side:
(t + -5)(t + -5) = -25

Can't calculate square root of the right side.

The solution to this equation could not be determined.